Question 1 of 1 | |
Question 1-56.5 | 10 points |
A 20.0-L nickel container was charged with 0.847 atm of xenon gas and 1.50 atm of fluorine gas at 400.C. The xenon and fluorine react to form xenon tetrafluoride. What mass (g) of xenon tetrafluoride can be produced assuming 100 % yield?
g XeF4
g XeF4
|
Hint 1 |
Balance the equation for the reaction. 1 Xe + 2 F2 1 XeF4 Your answer is correct. Great job! |
Hint 2 |
How many moles of F2 are present? .543 mol F2 Keep up the excellent work. |
View more information on this hint |
Hint 3 |
How many moles of Xe are present? .306 mol Xe Your answer is correct. Great job! |
More information on this hint |
Use the ideal gas law. |
Hint 4 |
The mole ratio between Xe and F2 is to Keep up the excellent work. |
View more information on this hint |
Hint 5 |
How many moles of Xe are required to react completely with the F2? .272 mol Xe Keep up the excellent work. |
Hint 6 |
How many moles of F2 are required to react completely with the Xe? .612 mol F2 You are correct. Nice job! |
Hint 7 |
How many moles of XeF4 can be produced? .272 mol XeF4 Excellent job! |