Question 1 of 1

Question 1

8 points

It took 43.00 mL of 0.5065 M sodium hydroxide to react completely with 3.210 g of a weak acid HA. What is the molar mass of the weak acid?

g/mol

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Hint 1

Balance the equation for the reaction —select—123 HA + —select—123 NaOH —select—123 NaA + —select—123 H2O Good job on this problem! Top of page

Hint 2

How many moles of NaOH are present in 43.00 mL of a 0.5065 M solution of sodium hydroxide? .02178 mol You are correct. Nice job! Top of page

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Hint 3

The mole ratio betwen HA and NaOH is —select—123 to —select—123 Well done! Your effort has paid off. Top of page

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Hint 4

How many moles of HA are required to react completely with the NaOH? .02178 mol Excellent job! Top of page

Hint 5

To convert moles of HA to molar mass, we need to divide the —select—massmolesmolar massvolumemolarity by the —select—massmolesmolar massvolumemolarity Keep up the good work. Top of page

Question 1 of 1